Weighing cents boxes, simultaneous equatns and predictions
Posted: Tue Oct 29, 2024 1:30 pmGot a $25 box of cents from the bank. I weighed it. Weighs 14.8625 pounds ( 14lbs. 13.8 oz) . I am not factoring cardboard and wrapper weights into this calculation. Used this set of simultaneous equations to make a prediction of copper percentage:
X = Zincoln count
Y = non Zincoln ( 95% Cu mostly) count
For a $25 box:
X + Y =2500
Box weighs 237.8 ounces ( 14.8625 lbs * 16 ounces/lb)
Zincoln weighs 0.088 ounces
95% Cu cent weighs 0.109 ounces
(X * 0.088) + ( Y* 0.109) = 237.8
Using this calculator:
https://www.symbolab.com/solver/simulta ... calculator
I will plug in the 2 equations
X + Y = 2500
0.088X + 0.109Y = 237.8
The calculator gives me X = 1652 and Y =17800/21 = 847
This works out to nearly a 33% Cu yield.
I will be going through the box this week. I'll let you all know how it turns out.
X = Zincoln count
Y = non Zincoln ( 95% Cu mostly) count
For a $25 box:
X + Y =2500
Box weighs 237.8 ounces ( 14.8625 lbs * 16 ounces/lb)
Zincoln weighs 0.088 ounces
95% Cu cent weighs 0.109 ounces
(X * 0.088) + ( Y* 0.109) = 237.8
Using this calculator:
https://www.symbolab.com/solver/simulta ... calculator
I will plug in the 2 equations
X + Y = 2500
0.088X + 0.109Y = 237.8
The calculator gives me X = 1652 and Y =17800/21 = 847
This works out to nearly a 33% Cu yield.
I will be going through the box this week. I'll let you all know how it turns out.